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The first section of the BMAT can be especially challenging for candidates, as it is aptitude-based, rather than knowledge-based. Here, we present 10 difficult questions from our question bank. We’ve removed the multiple choice options to make these questions even more difficult – all questions in ourÂ bankÂ include four options to choose from.
Assume the smallest possible size of the secondary school is x students.
It is known that (1/9) of x play football.
Using the other information it can be deduced that:
(1/54) of x are strikers that play in the A team.
Since the number of strikers that play for the A team must be a whole number, the answer must be 54 pupils, A.
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The beaker is Â¼ full of Hydrochloric acid.
This means it contains 50 ml of Hydrochloric acid. When 40 ml of water is added to the beaker the total volume increases to 90 ml.
Since the Hydrochloric acid makes up 5/9 of the total volume its concentration is now 5/9 of its original value.
To decrease the concentration of Hydrochloric acid to 1/3 of its original value it must make up one third of the total volume of the solution.
This can be achieved by adding another 60 ml of water to the beaker.
Total volume = 50 + 40 + 60 = 150 ml
Volume of Hydrochloric acid = 50 ml
Fraction of Hydrochloric acid = 50 / 150 = 1/3, meaning D is the answer.
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This is a problem that can be solved with a bit of strategic thinking.
This way, you have successfully measured 4 litres of water using only a 5-litre and a 3-litre container.
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To determine who cooked the risotto, we use the given clues to eliminate possibilities. Since Claire didn’t cook sushi or lasagna, and Emma cooked pizza, they cannot be the ones who prepared risotto. David’s dish wasn’t risotto, so he is also ruled out. We know Ben cooked pasta, so he didn’t prepare risotto either. Alice’s dish had the most ingredients, and since there are no other clues, Alice must have prepared the risotto.
The sequence represents the squares of consecutive natural numbers: 2^2 = 4, 3^2 = 9, 4^2 = 16, 5^2 = 25, 6^2 = 36. To find the next three numbers, continue the pattern: 7^2 = 49, 8^2 = 64, 9^2 = 81.
By following the clues, we can determine the seating arrangement around the table. Alice is opposite Bob, so Carol and Dave must be sitting next to each other. Since Carol is not opposite Alice, Carol and Dave must be sitting in the two seats next to Alice. Thus, Alice, Carol, and Dave are seated in consecutive seats. Bob is opposite Alice, which leaves him in the remaining seat. The seating arrangement, starting from any position, is: Alice, Carol, Dave, Bob.
Learn time-efficient BMAT strategies and practice with reflective BMAT questions & worked solutions.
The given clues help establish the order of the houses. The red house is to the left of the green house, so it must be in the first position. The blue house is to the right of the green house but not next to the red house, so it occupies the third position. The yellow house is to the right of the blue house and left of the purple house, indicating it is in the second position. The purple house must be in the fifth position. The order from left to right is: red, yellow, green, blue, purple.
From the given clues, we can deduce the cities in which each friend lives. Since Bailey lives in Paris and Eden doesn’t live in Tokyo, Eden must live in either London, New York, or Sydney. Chris lives in either Sydney or Tokyo, and Drew lives in New York or Sydney, which means Chris cannot live in Sydney. Therefore, Chris lives in Tokyo. Drew must then live in Sydney. As Alex doesn’t live in London or Tokyo, Alex must live in New York. Thus, the final city assignments are: Alex – New York, Bailey – Paris, Chris – Tokyo, Drew – Sydney, and Eden – London.
The coded message “8-5-12-12-15” corresponds to the letters H-E-L-L-O using the given code. Each number corresponds to the position of the corresponding letter in the alphabet (A=1, B=2, etc.). Therefore, 8 represents the 8th letter, which is H, 5 represents E, and so on. Decoding the message yields the word “HELLO.”
The sequence represents the sum of consecutive odd numbers. The pattern starts with 1 (1 + 1 = 2), then adds two consecutive odd numbers successively to get the next terms: 1 + 3 + 5 = 9 (2 + 9 = 11), 9 + 7 + 9 = 25 (11 + 25 = 36). Continuing the pattern, we add 11 + 9 + 11 = 31 to 36 to get the next two terms: 36 + 31 = 67 and 67 + 41 = 108. Thus, the missing numbers are 67 and 108.
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